Graphing Quadratic Functions
Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions ofX^2y^2=9 (an equation of a circle with a radius of 3) sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has
Construct the graph x^2+y^2=9
Construct the graph x^2+y^2=9-Therefore x2=9y2 And x is the squareroot of that (with two values plus and minus) Choose a value of y, and work out x2 and therefore the This is the standard form for the graph of a circle!
Graphing Square Root Functions
Let's look at the graph its center will be at (0,0),Graph x^2y^2=9 x2 y2 = 9 x 2 y 2 = 9 This is the form of a circle Use this form to determine the center and radius of the circle (x−h)2 (y−k)2 = r2 ( x h) 2 ( y k) 2 = r 2 Match theAs you can see, this graph is of 2 parallel lines This is because the equation x 2 2xy y 2 = 9 can be factored into (xy)(xy) = 9 which is equivalent to (xy) 2 = 9 Then, to simplify this
How can you graph x2 y2 equals 9?Make x the subject of the second equation, so x=2y Substitute x=2y into x^2y^2=9, to give (2y)^2y^2=9 Expand the brackets using FOIL to give 44yy^2y^2=9 By grouping like terms(xh)^2(yk)^2=r^2 Doesn't a circle have infinitely many lines of symmetry?
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This is almost the standard form for the equation of a circle Let's modify it to read (x −0)2 (y 2)2 = 9 Now we see that it is a circle with centre at ( 0, − 2) and radius √9 = 3 This Stepbystep explanation Without graphing, this is the equation of a circle with center at the origin, (0, 0) and with a radius of 3 units The general equation of a circle with
Incoming Term: construct the graph x^2+y^2=9, construct the graph of x^2+y^2=9 by drawing the line x+y=1,
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